First Steps in Geometry: A Series of Hints for the Solution of Geometrical Problems with Notes on Euclid, Useful Working Propositions and Many ExamplesLongmans, Green, and Company, 1887 - 180 páginas |
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Página 6
... A B and BC ( Fig . 2 ) , and taking P as the given point , to draw PDE , so that PD and DE might be as nearly equal as possible . The proper way , however , is to draw a straight line , PE , bisect it in D , and through the points DE to ...
... A B and BC ( Fig . 2 ) , and taking P as the given point , to draw PDE , so that PD and DE might be as nearly equal as possible . The proper way , however , is to draw a straight line , PE , bisect it in D , and through the points DE to ...
Página 10
... AB ( Fig . 6 ) is bisected in C , and CD is drawn at right angles to AB . From any FIG . 6 . point E in CD lines are drawn to A and B. Show that E A is equal to E B. Having constructed a figure in accordance with these data , we go over ...
... AB ( Fig . 6 ) is bisected in C , and CD is drawn at right angles to AB . From any FIG . 6 . point E in CD lines are drawn to A and B. Show that E A is equal to E B. Having constructed a figure in accordance with these data , we go over ...
Página 11
... equal to E B. Now , we cannot fail to see that the data involve the equality of the triangles ACE , CE B , by Euc ... A B , then AC , CE , being equal , respectively , to B C ANALYSIS AND SYNTHESIS . 11.
... equal to E B. Now , we cannot fail to see that the data involve the equality of the triangles ACE , CE B , by Euc ... A B , then AC , CE , being equal , respectively , to B C ANALYSIS AND SYNTHESIS . 11.
Página 12
... equal , respectively , to B C , C E , the triangles AC E , B C E are equal in all respects ; therefore the angle CA ... A B equal to A C , the angle ABC equal to the angle B C A , and also ( see the proof of Euc . I. , 5 ) , the angle ...
... equal , respectively , to B C , C E , the triangles AC E , B C E are equal in all respects ; therefore the angle CA ... A B equal to A C , the angle ABC equal to the angle B C A , and also ( see the proof of Euc . I. , 5 ) , the angle ...
Página 13
... AB H equal to the angle A CH , and also AB , AH equal to CA , AH , respectively . But these relations are not sufficient . Seeing , however , the probability that the solution of our problem lies in this particular direction , we search ...
... AB H equal to the angle A CH , and also AB , AH equal to CA , AH , respectively . But these relations are not sufficient . Seeing , however , the probability that the solution of our problem lies in this particular direction , we search ...
Otras ediciones - Ver todas
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Vista de fragmentos - 1888 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2018 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2013 |
Términos y frases comunes
A B C D A B is equal ABCD angle ABC angle BA angle equal base bisector bisects the angle circle diagonals divided equal and parallel equal angles equal sides equal to DC equal to half equal to twice Euclid exterior angles given angle given line given point given straight line greater Hence hypotenuse intersect isosceles triangle KHGE lines bisecting lines drawn locus maxima and minima obtuse opposite sides parallelogram perpendicular point F problem produced proof Prop proposition quadrilateral R. A. PROCTOR rect rectangle A C rectangle contained respects Euc rhombus right angles right-angled triangle sides A B solution square on CD squares on A C straight line A B theorems trapezium triangle ABC trisected twice the rectangle vertex vertical angle
Pasajes populares
Página 80 - If two triangles have two sides of the one equal to two sides of the...
Página 144 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Página 175 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Página 136 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.