First Steps in Geometry: A Series of Hints for the Solution of Geometrical Problems with Notes on Euclid, Useful Working Propositions and Many ExamplesLongmans, Green, and Company, 1887 - 180 páginas |
Dentro del libro
Resultados 1-5 de 21
Página 3
... contained in Euclid , or not readily deducible from Euclid's propositions , shall be made use of . Lastly , there are deductions of a more advanced character , and propositions which present themselves in the solution of problems in ...
... contained in Euclid , or not readily deducible from Euclid's propositions , shall be made use of . Lastly , there are deductions of a more advanced character , and propositions which present themselves in the solution of problems in ...
Página 5
... contained by two given straight lines , to draw a straight line so that the part intercepted between the two given straight lines may be equal to the part between the given point and the nearest line . Here the natural process , in ...
... contained by two given straight lines , to draw a straight line so that the part intercepted between the two given straight lines may be equal to the part between the given point and the nearest line . Here the natural process , in ...
Página 24
... contained in Euclid is that of Book I. , 1 We have seen this problem given with the proviso that no problem beyond Euc . I. , 1 , shall be made use of . In this case the student will see at once that if , with centres A and B , and ...
... contained in Euclid is that of Book I. , 1 We have seen this problem given with the proviso that no problem beyond Euc . I. , 1 , shall be made use of . In this case the student will see at once that if , with centres A and B , and ...
Página 36
... contained by the equal sides . Hence C E is at right angles to QL and bisects QL in E. It is a very obvious con- sideration , at this point , that if we join C , L we shall have QC , L an isosceles triangle , C , Q being clearly equal ...
... contained by the equal sides . Hence C E is at right angles to QL and bisects QL in E. It is a very obvious con- sideration , at this point , that if we join C , L we shall have QC , L an isosceles triangle , C , Q being clearly equal ...
Página 79
... contained by the sides ( as distinguished from the angles contained be- tween the base and either side ) , yet , since any side might have been taken for base , the equality of each angle of one triangle to the corresponding angle of ...
... contained by the sides ( as distinguished from the angles contained be- tween the base and either side ) , yet , since any side might have been taken for base , the equality of each angle of one triangle to the corresponding angle of ...
Otras ediciones - Ver todas
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Vista de fragmentos - 1888 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2018 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2013 |
Términos y frases comunes
A B C D A B is equal ABCD angle ABC angle BA angle equal base bisector bisects the angle circle diagonals equal and parallel equal angles equal sides equal to DC equal to half equal to twice Euclid exterior angles given angle given line given point given straight line greater Hence hypotenuse intersect isosceles triangle KHGE lines bisecting lines drawn locus maxima and minima obtuse opposite sides parallelogram perpendicular point F problem produced proof Prop proposition quadrilateral R. A. PROCTOR rect rectangle A C rectangle contained respects Euc rhombus right angles right-angled triangle sides A B solution square on CD squares on A C straight line A B theorems trapezium triangle ABC twice the rectangle vertex vertical angle
Pasajes populares
Página 80 - If two triangles have two sides of the one equal to two sides of the...
Página 144 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Página 175 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Página 136 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.