First Steps in Geometry: A Series of Hints for the Solution of Geometrical Problems with Notes on Euclid, Useful Working Propositions and Many ExamplesLongmans, Green, and Company, 1887 - 180 páginas |
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Página 6
... BC ( Fig . 2 ) , and taking P as the given point , to draw PDE , so that PD and DE might be as nearly equal as possible . The proper way , however , is to draw a straight line , PE , bisect it in D , and through the points DE to draw ...
... BC ( Fig . 2 ) , and taking P as the given point , to draw PDE , so that PD and DE might be as nearly equal as possible . The proper way , however , is to draw a straight line , PE , bisect it in D , and through the points DE to draw ...
Página 8
... equal angles with any side . It will be noticed , also , that neither diagonal bisects the other . If we had a ... BC , CD , and D A. It is sometimes convenient to draw a part of the figure in darker lines than the rest . We may dis ...
... equal angles with any side . It will be noticed , also , that neither diagonal bisects the other . If we had a ... BC , CD , and D A. It is sometimes convenient to draw a part of the figure in darker lines than the rest . We may dis ...
Página 11
... equal to E B. Now , we cannot fail to see that the data involve the equality of the triangles ACE , CE B , by Euc ... BC , CE , the angles ACE and BCE will be equal ( Euc . I. , 8 ) ; but these angles are equal , being right angles ...
... equal to E B. Now , we cannot fail to see that the data involve the equality of the triangles ACE , CE B , by Euc ... BC , CE , the angles ACE and BCE will be equal ( Euc . I. , 8 ) ; but these angles are equal , being right angles ...
Página 12
... equal , respectively , to B C , C E , the triangles AC E , B C E are equal in all respects ; therefore the angle CA E will be equal to the angle CBE . Now , these angles are equal ; therefore we might expect the reversal of the process ...
... equal , respectively , to B C , C E , the triangles AC E , B C E are equal in all respects ; therefore the angle CA E will be equal to the angle CBE . Now , these angles are equal ; therefore we might expect the reversal of the process ...
Página 16
... BC , and we know from Euc . I. , 19 , that if DC is greater than B C , then ... equal to the angle AC B ( Euc . I. , 5 ) , and two angles of a triangle ... BC . We will next try a proposition slightly more difficult . 16 GEOMETRICAL ...
... BC , and we know from Euc . I. , 19 , that if DC is greater than B C , then ... equal to the angle AC B ( Euc . I. , 5 ) , and two angles of a triangle ... BC . We will next try a proposition slightly more difficult . 16 GEOMETRICAL ...
Otras ediciones - Ver todas
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Vista de fragmentos - 1888 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2018 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2013 |
Términos y frases comunes
A B C ABCD acute apply base bisector bisects the angle Book centre circle construction contained converse deductions described determine diagonals diameter difference distances divided double draw drawn equal equal to BC established Euclid Example figure four given point given straight line greater half Hence intersect isosceles triangle join less line A B locus manner meet method notice obvious opposite sides pair parallel parallelogram pass perpendicular problem produced proof Prop properties proposition prove quadrilateral rect rectangle A B relation remaining respects right angles shown solution solved square squares on A C student Suppose taken third triangle ABC twice the rectangle vertical angle
Pasajes populares
Página 80 - If two triangles have two sides of the one equal to two sides of the...
Página 144 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Página 175 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Página 136 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.