First Steps in Geometry: A Series of Hints for the Solution of Geometrical Problems with Notes on Euclid, Useful Working Propositions and Many ExamplesLongmans, Green, and Company, 1887 - 180 páginas |
Dentro del libro
Resultados 1-5 de 22
Página 12
... intersect in H , show that AH bisects the angle BAC . Let us go over our data : —We have A B equal to A C , the angle ABC equal to the angle B C A , and also ( see the proof of Euc . I. , 5 ) , the angle ABG equal to the angle A C F ...
... intersect in H , show that AH bisects the angle BAC . Let us go over our data : —We have A B equal to A C , the angle ABC equal to the angle B C A , and also ( see the proof of Euc . I. , 5 ) , the angle ABG equal to the angle A C F ...
Página 44
... intersect K L M in L. Then , if we can show that BH , drawn as before , falls between BA and B L , our surmise will have been proved to be correct . Now the angle H BE , by our construction , is equal to the angle HEB ; M FIG . 22 ...
... intersect K L M in L. Then , if we can show that BH , drawn as before , falls between BA and B L , our surmise will have been proved to be correct . Now the angle H BE , by our construction , is equal to the angle HEB ; M FIG . 22 ...
Página 48
... intersect in A. From A equal parts A D and A E are cut off from AB , A C respectively . ED is bisected in F. Find the locus of all such points as F. Take A G equal to AH , AK equal to AL , and bisect G H in M , KL in N. Then it seems ...
... intersect in A. From A equal parts A D and A E are cut off from AB , A C respectively . ED is bisected in F. Find the locus of all such points as F. Take A G equal to AH , AK equal to AL , and bisect G H in M , KL in N. Then it seems ...
Página 55
... intersect the circle FG E. If it intersects that circle in two points , G and E , it is clear that each of these points satisfies the required conditions . For C G is equal to D ( const . ) , and G A is equal to G B ( Euc . I. , 4. See ...
... intersect the circle FG E. If it intersects that circle in two points , G and E , it is clear that each of these points satisfies the required conditions . For C G is equal to D ( const . ) , and G A is equal to G B ( Euc . I. , 4. See ...
Página 56
... intersect , the pro- blem is insoluble . Let us take , as another instance , the following problem : - Ex . 20. - Let AB ( Fig . 30 ) be a given straight line , C a given angle , D a given point within the given circle EFG . It is ...
... intersect , the pro- blem is insoluble . Let us take , as another instance , the following problem : - Ex . 20. - Let AB ( Fig . 30 ) be a given straight line , C a given angle , D a given point within the given circle EFG . It is ...
Otras ediciones - Ver todas
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Vista de fragmentos - 1888 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2018 |
First Steps in Geometry: A Series of Hints for the Solution of Geometrical ... Richard Anthony Proctor Sin vista previa disponible - 2013 |
Términos y frases comunes
A B C D A B is equal ABCD angle ABC angle BA angle equal base bisector bisects the angle circle diagonals equal and parallel equal angles equal sides equal to DC equal to half equal to twice Euclid exterior angles given angle given line given point given straight line greater Hence hypotenuse intersect isosceles triangle KHGE lines bisecting lines drawn locus maxima and minima obtuse opposite sides parallelogram perpendicular point F problem produced proof Prop proposition quadrilateral R. A. PROCTOR rect rectangle A C rectangle contained respects Euc rhombus right angles right-angled triangle sides A B solution square on CD squares on A C straight line A B theorems trapezium triangle ABC twice the rectangle vertex vertical angle
Pasajes populares
Página 80 - If two triangles have two sides of the one equal to two sides of the...
Página 144 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Página 175 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Página 136 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.