PAPER I. FOR SECOND MATE. (1) Multiply 192 by 15, by common logs. Divide 694 by 327, by common logs. (3) (2) 1 S.S.W. 9 9 West. A point of land in 2 9 7 lat. 40° S. 3 8 4 long. 160° E. 4 8 bearing by compass 5 N.W. 9 5 W.S.W. 1 N.N.E. 6 8 9 Dist. 7 miles. 7 8 1 8 7 5 9 N.N.E. 7 0 East. 용 10 6 4 11 7 12 8 7 1 East. 9 3 S.S.E. 11 Variation 1. pts. W. 2 9 0 3 9 4 4 9 3 5 S.E. by E. 8 7 N.E. by E. A current set the 6 8 5 ship by compass 7 8 8 N. W. 8 8 9 South. 8 2 E.S.E. 1 Dist. 20 miles from 10 8 2 the time the depar11 8 6 ture was taken to 12 9 0 the end of the day. Correct the courses for leeway and variation, find the latitude and longitude in, and the course and distance made good during the 24 hours. (4) 1870, January 2nd, in longitude 120° 30' W., the observed meridian altitude of the Sun's 1.1. was 46° 30', bearing N., index error 1' 40", height of the eye 16 feet. Find the latitude. (5) In latitude 22° 19', the departure made good was 102 miles. Required the difference of longitude by parallel sailing. (6) Required the course and distance from A to B, by Mercator's sailing. Lat. A.. 24° 39' N. Long. A. ,140° 15' E. ADDITIONAL FOR ONLY MATE. (7) 1870, May 9th. Find the A. M. and P. M. tides at Cape Clear, Cuxhaven, and Ramsgate. (8) 1870, September 2nd, at 6h. 42m. P. M. apparent time at ship, in lat. 51° 32 N., long. 3° 26' E., the magnetic amplitude of the Sun was W. 36° 38' N. Find the variation. (9) 1870, January 6th, P. M. at ship, in lat. 24° 12' S. the observed altitude of the Sun's 1. 1. was 12° 17' 20", index error + 1' 10", height of the eye 17 feet, time by chronometer 6d. 9h. 14m. 10s., which was slow on Greenwich mean time 5m. 50s., on October 30th, 1869, and losing 23.6 daily. Find the longitude. ADDITIONAL FOR FIRST MATE. (10) 1870, May 24, at 4h. 10m. P. M. mean time at ship, in lat. 34° 22' S., long. 18° 24' E., the Sun's bearing by compass was N. 62° 50' W., the observed altitude of the Sun's l. l. was 23°, height of the eye 12 feet. Find the variation. (11) 1870, January 27th, P. M. at ship, in lat. by account 42° 40'S., long. 30° 30' W., the observed altitude of the Sun's l. 1. near the meridian North of the observer was 64° 59' 27", index error + 30", height of the eye 24 feet, time by watch 27d. 2h. 25m. 21s., which was fast on apparent time at ship lh. 59m. 47s., and the difference of longitude since the error was taken, to the westward, was 17 miles. Find the true latitude. ADDITIONAL FOR MASTER. (12) 1870, February 14th, the observed meridian altitude of the star Vega was 27° 41' 10", bearing N., index error + 3, height of the eye 17 feet. Find the latitude. PAPER II. FOR SECOND MATE. (1) Multiply 374 by 21, by common logs. 1 N.W. 6 4 W.S.W. 1: A point of land in 2 6 3 lat. 36° 47' N. 3 6 2 long. 106° 54' E. 5 bearing by compass W. by S. 4 7 N.W. by N. 14 N.N.W. 6 5 3 Dist. 27 miles. 7 7 6 8 7 4 9 West. 5 1 N. N.W. 13 10 5 4 11 5 5 12 6 0 1 W. N.W. 6 0 S.W. 1 Variation 23 pts. E. 2 6 2 3 6 7 4 7 1 5 N.E. 5 7 E.S.E. A current set the 6 6 0 ship by compass 7 6 3 S.W. 8 6 0 9 E.S.E. 4 9 South. 13 Dist. 14 miles from 10 5 1 the time the depar4 7 ture was taken to 12 5 3 the end of the day. (4) 1870, February 19th, in longitude 49° 50' E., the observed meridian altitude of the Sun's 1.l. was 40° 10' 20", bearing N., index error + 4' 16", height of the eye 20 feet. Find the latitude, 11 (5) In latitude 40°16', the departure made good was 230 miles. Required the difference of longitude by parallel sailing. (6) Required the course and distance from A to B, by Mercator's sailing. Lat. A..16° 24' N. Long. A. . 15° 29' W. ADDITIONAL FOR ONLY MATE. (7) 1870, June 10th. Find the A. M. and P. M. tides at Chatham, Shields, and Torbay. (8) 1870, October 30th, at 5h. 3m. A. M. apparent time at ship, Lat. 39o 49 S., longitude 80° 30' W., the magnetic amplitude of the Sun was E. 6° 34' S. Find the variation. (9) 1870, February 19th, A. M. at ship, in lat. 17° 24' N., the observed altitude of the Sun's l. 1. was 20° 14' 40", index error—4' 10", height of the eye 16 feet, time by chronometer 18d. 17h. 46m. 23s., which was fast on Greenwich mean time 20m. 14s., on January 1st, and gaining daily 18.5. Find the longitude. ADDITIONAL FOR FIRST MATE. (10) 1870, June 16th, at 5h. 45m. A. M. mean time at ship, in lat. 36° 6' N., long. 5° 15' W., the Sun's bearing by compass was S. 88° 14' E., the observed altitude of the Sun's l. 1. was 10° 30', height of the eye 14 feet. Find the variation. (11) 1870, February 28th, A. M. at ship, in lat. by account 53° 30' N., long. 20° 30' E., the observed alt. of the Sun's 1. 1. near the meridian, South of the observer, was 27° 15' 20", index error 1' 14", height of the eye 17 feet, time by watch 27d. 22h. 14m. 6s., which was slow on apparent time at ship 47m. 51s., but since the error was determined the ship has made 15 miles d.long. to the E. Find the true latitude. ADDITIONAL FOR MASTER. (12) 1870, March 20th, the observed meridian altitude of the star Canopus, was 64° 10' 40", bearing S., index error -1' 50", height of the eye 10 feet. Find the latitude, F (1) Multiply 2014 by 4, by common logs. OOOO A COM 1 N.E. by E. 3 4 S.E. by E. 11 A point of land in 2 2 7 lat. 50° 27' N. 3 4 9 long. 24° 16' W. 4 5 6 bearing by compass 5 N.W. 7 N.N.E. N.E. } E. 6 5 Dist. 15 miles. 7 5 9 8 6 8 9 E.N.E. 4 7 N. 1 10 5 9 11 5 2 12 6 3 1 S.E. by S. 5 7 S.W. by S. 1 Variation 22 pts. E. 2 4 9 3 3 6 4 3 1 5 S.S.W. 2 5 W. A current set the 6 2 7 ship by compass 7 2 3 S.W. 1 W. 8 3 4 9 W. 3 7 N.N.W. * Dist. 16 miles from 10 4 5 the time the depar11 4 9 ture was taken to 12 3 6 the end of the day. (4) 1870, April 21st, in longitude 16° 30' E., the observed meridian altitude of the Sun's l. 1. was 30° 16' 10', bearing N., index error + 1' 15", height of the eye 18 feet. Find the latitude. |