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(5) In latitude 31°, the departure made good was 12 miles. Required the d.long. by parallel sailing.

(6) Required the course and distance, by Mercator's sailing, from A to B.

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(8) 1870, May 7th, at 5h. 30m. P. M. apparent time at ship, in latitude 24° 17′ S., longitude 75° 45′ E., the Sun's observed magnetic amplitude was W. 7° 29′ S. Find the variation.

(9) 1870, October 30th, P. M. at ship, in latitude 55° N., the observed altitude of the Sun's 1. 1. was 12° 46', height of the eye 20 feet, time by chronometer 30d. 9h. 56m. 20s., which was slow 3m. 17s. on mean time at Greenwich, on June 20th, and losing daily 3s-2. Find the longitude by chronometer.

ADDITIONAL FOR FIRST MATE.

(10) 1870, January 10th, mean time at ship 3h. 46m. P. M., in latitude 35° 20′ N., longitude 30° 45′ W., the Sun's bearing by compass was S. 70° 20′ W., altitude of the Sun's I.1. 11° 31', height of the eye 14 feet. Find the

variation.

(11) 1870, February 4th, P. M. at ship, in latitude by account 42° N., longitude 30° E., the observed altitude of the Sun's 1.1. near the meridian, South of the observer, was 31° 37′ 10′′, index error + 1' 10", height of the eye 16 feet, time by watch 4d. 2h. 17m. 5s., which had been found to be 2h. fast on apparent time at ship, but since the error was determined the d.long. made to the W. was 20 miles. Find the latitude by reduction to the meridian.

ADDITIONAL FOR MASTER.

(12) 1870, July 6th, the observed meridian altitude of the star Fomalhaut was 46° 52', bearing S., height of the eye 16 feet. Find the latitude.

PAPER IX.

FOR SECOND MATE.

(1) Multiply 90 by 25, by common logs.
(2) Divide 8410 by 396, by common logs.

(3)

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1 W. by N.

2

7

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1432

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7 1 S.W. by S. 2 A point of land in

lat. 50° 6' N.

long. 127° 43′ W. bearing by compass

N.N.W. W.
Dist. 19 miles.

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(4) 1870, September 5th, in longitude 150° 40′ W., the observed

meridian altitude of the Sun's 1.1. was 60° 30′ 7′′, bearing S., index error +4′13′′, height of the eye 23 feet. Find the latitude.

(5) In latitude 31°, the departure made good was 12 miles. Required the d.long. by parallel sailing.

(6) Required the course and distance, by Mercator's sailing,

from A to B.

A-Lat. 16° 34' S.

B-Lat. 24 35 S.

A-Long. 169° 45′ E.

B-Long. 174 56 W.

ADDITIONAL FOR ONLY MATE.

(7) 1870, February 17th.

Find the A. M. and P. M. tides

at Blyth, Hull, and Ipswich.

(8) 1870, May 7th, at 5h. 30m. P. M. apparent time at ship, in latitude 24° 17′ S., longitude 75° 45′ E., the Sun's observed magnetic amplitude was W. 7° 29′ S. Find the variation.

(9) 1870, October 30th, P. M. at ship, in latitude 55° N., the observed altitude of the Sun's 1. 1. was 12° 46', height of the eye 20 feet, time by chronometer 30d. 9h. 56m. 20s., which was slow 3m. 17s. on mean time at Greenwich, on June 20th, and losing daily 3s.2. Find the longitude by chronometer.

ADDITIONAL FOR FIRST MATE.

(10) 1870, January 10th, mean time at ship 3h. 46m. P. M., in latitude 35° 20′ N., longitude 30° 45′ W., the Sun's bearing by compass was S. 70° 20′ W., altitude of the Sun's I.1. 11° 31', height of the eye 14 feet. Find the

variation.

(11) 1870, February 4th, P. M. at ship, in latitude by account 42° N., longitude 30° E., the observed altitude of the Sun's 1.1. near the meridian, South of the observer, was 31° 37′ 10′′, index error +1'10", height of the eye 16 feet, time by watch 4d. 2h. 17m. 5s., which had been found to be 2h. fast on apparent time at ship, but since the error was determined the d.long. made to the W. was 20 miles. Find the latitude by reduction to the meridian.

ADDITIONAL FOR MASTER.

(12) 1870, July 6th, the observed meridian altitude of the star Fomalhaut was 46° 52', bearing S., height of the eye 16 feet. Find the latitude.

PAPER X.

FOR SECOND MATE.

(1) Multiply 276 by 7, by common logs.
(2) Divide 4091 by 396, by common logs.

(3)

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(4) 1870, November 1st, in longitude 40° 30′ E., the observed meridian altitude of the Sun's 1.1. was 50° 6' 40′′, bearing 1′ 20′′, height of the eye 19 feet.

S., index error
Find the latitude.

(5) In latitude 32° 19′, the departure made good was 130 miles. Required the d.long. by parallel sailing.

(6) Required the course and distance by Mercator's sailing, from A to B.

A-Lat. 37° 44′ S.

A-Long. 49° 51′ W.

B-Lat. 49 14 S.

B-Long. 39 16 W.

ADDITIONAL FOR ONLY MATE.

(7) 1870, March 29th. Required the A. M. and P. M. tides at Dublin, Sheerness, and Peterhead.

(8) 1870, June 8th, at 4h. 27m. A. M., apparent time at ship, in latitude 43° 16' N., longitude 167° 30′ W., the Sun's magnetic amplitude was East. Find the true amplitude and variation.

(9) 1870, November 15th, A. M. at ship, in latitude 17° 14′ S. the observed altitude of the Sun's 1. 1. was 30° 15′ 15′′, index error + 3′ 10′′, height of the eye 17 feet, time by chronometer 14d. 20h. 13m. 16s., which was fast 17m. 21s. on mean noon at Greenwich, on the 26th August, and gaining daily 4s.5. Find the longitude by chronometer.

ADDITIONAL FOR FIRST MATE.

(10) 1870, February 14th, at 7h. 18m. A. M. mean time at ship, in latitude 26° 29′ S., longitude 60° E., the observed altitude of the Sun's 1. 1. was 22° 55', height of the eye 15 feet, bearing by azimuth compass S.E. E. Find the variation.

(11) 1870, March 17th, P. M. at ship, in latitude by account 15° N., longitude 145° W., the observed altitude of the Sun's 1. 1. near the meridian, South of the observer, was 71° 7′ 40′′, height of the eye 19 feet, time by watch 11h. 46m. 37s., which had been found to be 49m. 54s. slow on apparent time at ship, but since the error was determined the ship has made 15 miles d.long. to the E. Find the latitude by reduction to the meridian.

ADDITIONAL FOR MASTER.

(12) 1870, September 21st, the observed meridian altitude of the star ẞ Aquila, bearing S., was 56° 47′ 10′′, height of the eye 20 feet. Find the latitude.

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