War-ships: A Text-book on the Construction, Protection, Stability, Turning, Etc., of War Vessels

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Longmans, Green, 1904 - 304 páginas

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Página 13 - For steel bars for combustion chamber stays the tensile breaking strength is to be between the limits of 2G and 30 tons per square inch, with an elongation of not less than 23 per cent, measured on the Standard test piece B.
Página 204 - BML = ~^r where /CP is the moment of inertia of the waterplane about a transverse axis passing through the centre of flotation; F = underwater volume of the ship.
Página 142 - ... two or three weeks, seven days or so being allowed for cooling. In this way the proportion of carbon on the face is increased, and the front is then capable of being hardened. The plate is first cemented as above, and then bent to the required shape and all necessary holes made in the surface. It is then heated and the face douched with cold water, which makes the front of the plate exceedingly hard.
Página 250 - ... less proportionate additions to the power. Passing from the destroyer to the cruiser of similar form but of 14,100 tons, and once more applying the scale of comparison, it will be seen that to 25 knots in the destroyer corresponds a speed of 47^ knots in the large vessel. In other words, the cruiser would not reach the condition where further increments of speed are obtained with comparatively moderate additions of power until she exceeded 47 knots, which is an impossible speed for such a vessel...
Página 142 - The object to be attained was a steel plate, without welds, having such a proportion of carbon in the surface that water cooling would produce a very hard face. As the thickness of the hard steel is practically constant for all thicknesses of plate, it follows that thin plates obtain relatively higher values of the figure of merit than thicker plates. That is, a 12-in.
Página 263 - ... upon them depend the power which the engines must develop to give the desired speed, the. weight of the hull, and the weight of certain parts of the equipment. In the finished ship the sum of the weights of hull-structure, propelling apparatus, equipment, coals, and load must equal the displacement to the specified load-line. Apart from experience, a problem involving so many unknown yet related quantities could scarcely be solved. On the basis of experience, recorded data, and model experiments...
Página 159 - The area of any trapezoid is equal to half the sum of the parallel sides multiplied by the distance between them.
Página 170 - Let b be half the breadth of the pontoon, I the length, D the depth of displacement for the upright position, d the length LE, or AV, and w the weight of a cubic foot of water. Then, the weight of the pontoon W = 26.DJ.M> and the weight of the wedge GLE = -~- x I . w.
Página 144 - On page 151, Naval Constructor Attwood, in explaining the reasons that prompted the British Admiralty in 1894 to abrogate the thick narrow belt of the Knyal Siwreign class and adopt the broad belt of the .Majestic class, says : — " 'Another point is that ships increase their draft as time goes on (about an inch yearly), owing to alterations and additions, so that the value of the belt gets less and less during the. course of years, unless steps are taken to reduce the draft.
Página 19 - When this kind of application is made it is only in case of danger, and therefore it is desired that the air in the auxiliary should be passed into the brake cylinder as quickly as possible, and in order to do this it is necessary to have the entire slide valve clear the port in the seat through which the air has to pass. In making ordinary stops this very quick action is not required, and in order to prevent the slide valve making the full stroke, there is a projection on the trainpipe side of the...

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